The molecular formula of an organic compound is C2 H4’ and O2. The compound is soluble in water and the addition of NaHCO3 to the aqueous solution of the compound CO2 evolved. Identify the organic compound. Write, with conditions and balanced chemical action, the reaction of the compound with ethanol.
WB Madhyamik 2018
Ans.
The name of the organic compound having the molecular formula C2 H4 O2 is acetic acid (CH, COOH).
Pure acetic acid is a colorless, inflammable, and pungent odor liquid. Its melting point is 16.7°C. It turns into a powdery substance like ice. It can blister if it comes in contact with the skin. It is miscible in water.
Reaction with NaHCO3: – (a) CH3COOH + NaHCO3 → CH3COONa+H2O+CO2 Sad Acetate
(b) Reaction with NaOH: – CH3COOH + NaOH CH3COONa + H2O (Sod. Acetate)
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